The roots of the equation $x^{2}+3 x-10=0$ are\

Question

Professor PC Thomas Classes · Answer

(a): We have, $x^{2}+3 x-10=0$\ $\Rightarrow x^{2}+5 x-2 x-10=0 \Rightarrow x(x+5)-2(x+5)=0$\ $\Rightarrow \quad(x-2)(x+5)=0 \Rightarrow x=2,-5$