The discriminant of the quadratic equation $3 \sqrt{3} x^{2}+10 x+\sqrt{3}=0$ is\

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(d): Given quadratic equation is $3 \sqrt{3} x^{2}+10 x+\sqrt{3}=0$ Comparing (i) with $a x^{2}+b x+c=0$, we have\ $a=3 \sqrt{3}, b=10, c=\sqrt{3}$\ So, discriminant, $D=b^{2}-4 a c=(10)^{2}-4 	imes 3 \sqrt{3} 	imes \sqrt{3}$\ $=100-36=64$\