The nature of roots of the quadratic equation $9 x^{2}-6 x-2=0$, is\

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(c) : Given, $9 x^{2}-6 x-2=0$ $$ D=b^{2}-4 a c=(-6)^{2}-4 \cdot 9 \cdot(-2)=36+72=108>0 $$ Since $b^{2}-4 a c>0$, there will be two distinct real roots.