The $14^{ ext {th }}$ term from the end of the A．P．$-11,-8,-5, \ldots$ ， 49 is ：\

Question

The $14^{	ext {th }}$ term from the end of the A．P．$-11,-8,-5, \ldots$ ， 49 is ：\

Professor PC Thomas Classes · Answer

(b) : Given A.P. is $-11,-8,-5, \ldots, 49$ Here, $a=-11, d=-8-(-11)=-8+11=3, l=49$\ $14^{	ext {th }}$ term from the end $=I-(n-1) d$\ $=49-(14-1)(3) \Rightarrow 49-(13)(3) \Rightarrow 49-39=10$\