The distance between the points $P\left(-\frac{11}{3}, 5\right)$ and $Q\left(-\frac{2}{3}, 5\right)$

Question

The distance between the points $P\left(-\frac{11}{3}, 5ight)$ and $Q\left(-\frac{2}{3}, 5ight)$ is :\

Professor PC Thomas Classes · Answer

(d) : Distance betweentwo points having coordinates ( $x_{1}, y_{1}$ ) and ( $x_{2}, y_{2}$ ) is given by $$ \sqrt{\left(x_{1}-x_{2}ight)^{2}+\left(y_{1}-y_{2}ight)^{2}} $$ Here, $x_{1}=\frac{-11}{3}, x_{2}=\frac{-2}{3}, y_{1}=5, y_{2}=5$ $$ \begin{array}{ll} 	herefore & 	ext { Required distance }(d)=\sqrt{\left(\frac{-11}{3}+\frac{2}{3}ight)^{2}+(5-5)^{2}} \ & =\sqrt{(-3)^{2}+(0)^{2}}=3 	ext { units } \end{array} $$