The point on the $x$-axis which is equidistant from $(-4,0)$ and $(10,0)$ is\

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Professor PC Thomas Classes · Answer

(d) : Let coordinates of the point on the $x$-axis be $P(x, 0)$. Let the given points be $A(-4,0)$ and $B(10,0)$, which also lie on $x$-axis.\ Since $P$ is equidistant from $A$ and $B$.\ $	herefore \quad x=\frac{-4+10}{2}=\frac{6}{2}=3$\ So, $P(3,0)$ is equidistant from $A(-4,0)$ and $B(10,0)$.