The centre of a circle whose end points of a diameter are $(-6,3)$ and $(6,4)$ is\

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Professor PC Thomas Classes · Answer

(c) : Let the coordinates of centre of the circle be $(x, y)$ and $A B$ be the given diameter.\ ∴ By using mid-point formula,\ \ we have $x=\frac{-6+6}{2}=0, y=\frac{3+4}{2}=\frac{7}{2}$\ ∴ Coordinates of $C$ are $\left(0, \frac{7}{2}ight)$.