If $5 an heta-12=0$, then the value of $\sin heta$ is :\

Question

If $5 	an 	heta-12=0$, then the value of $\sin 	heta$ is :\

Professor PC Thomas Classes · Answer

(b): Given, $5 	an 	heta-12=0$\ $\Rightarrow 	an 	heta=\frac{12}{5}=\frac{P}{B}$\ Let $P=12 k$ and $B=5 k$\ ∴ By Pythagoras theorem,\ $H^{2}=(12 k)^{2}+(5 k)^{2}$\ $\Rightarrow \quad H^{2}=144 k+25 k \Rightarrow H=13 k$\ $	herefore \quad \sin 	heta=\frac{P}{H}=\frac{12 \mathrm{k}}{13 \mathrm{k}}=\frac{12}{13}$