( $\cot heta+ an heta$ ) equals :\

Question

( $\cot 	heta+	an 	heta$ ) equals :\

Professor PC Thomas Classes · Answer

(a) : We have, $\cot 	heta+	an 	heta$\ $=\frac{\cos 	heta}{\sin 	heta}+\frac{\sin 	heta}{\cos 	heta}=\frac{\cos ^{2} 	heta+\sin ^{2} 	heta}{\sin 	heta \cos 	heta}$\ $=\frac{1}{\sin 	heta} \cdot \frac{1}{\cos 	heta} \quad$.\ $\left(\because \sin ^{2} 	heta+\cos ^{2} 	heta=1ight)$\ $=\operatorname{cosec} 	heta \sec 	heta$