If $5 an \beta=4$, then $\frac{5 \sin \beta-2 \cos \beta}{5 \sin \beta+2 \cos \beta}=$\

Question

If $5 	an \beta=4$, then $\frac{5 \sin \beta-2 \cos \beta}{5 \sin \beta+2 \cos \beta}=$\

Professor PC Thomas Classes · Answer

(a): Given, $	an \beta=\frac{4}{5}$ So, $\frac{5 \sin \beta-2 \cos \beta}{5 \sin \beta+2 \cos \beta}=\frac{5 	an \beta-2}{5 	an \beta+2}=\frac{5 	imes \frac{4}{5}-2}{5 	imes \frac{4}{5}+2}=\frac{1}{3}$