$(\sec A+ an A)(1-\sin A)$ equals\

Question

$(\sec A+	an A)(1-\sin A)$ equals\

Professor PC Thomas Classes · Answer

(d): Given, $(\sec A+	an A)(1-\sin A)$\ $=\left(\frac{1}{\cos A}+\frac{\sin A}{\cos A}ight)(1-\sin A)=\frac{(1+\sin A)}{\cos A}(1-\sin A)$\ $=\frac{1^{2}-\sin ^{2} A}{\cos A}\left(\because a^{2}-b^{2}=(a+b)(a-b)ight)$