If $\sec heta- an heta=\frac{1}{3}$, then the value of $(\sec heta+ an heta)$ is :\

Question

If $\sec 	heta-	an 	heta=\frac{1}{3}$, then the value of $(\sec 	heta+	an 	heta)$ is :\

Professor PC Thomas Classes · Answer

(d): Given, $\sec 	heta-	an 	heta=\frac{1}{3}$ As we know, $\sec ^{2} 	heta-	an ^{2} 	heta=1$\ $\Rightarrow(\sec 	heta-	an 	heta)(\sec 	heta+	an 	heta)=1$\ $\Rightarrow \quad \frac{1}{3} 	imes(\sec 	heta+	an 	heta)=1$\ [By (i)]\ $	herefore \sec 	heta+	an 	heta=3$\