Let the set $C=\left\{(x, y) \mid x^{2}-2^{y}=2023, x, y \in N\right\}$. Then $\sum_{(x, y) \in C}(x

Question

Let the set $C=\left\{(x, y) \mid x^{2}-2^{y}=2023, x, y \in Night\}$. Then $\sum_{(x, y) \in C}(x+y)$ is equal to $\_\_\_\_$ .\

Professor PC Thomas Classes · Answer

(46): We have, $x^{2}-2^{y}=2023$\ $\Rightarrow \quad 2^{y}=x^{2}-2023$\ $	herefore \quad$ Possible values of $(x, y)$ are $(45,1)$\ So, $\quad \sum_{(x, y) \in C}(x+y)=(45+1)=46$\