A peacock sitting on the top of a tree of height 10 m observes a snake moving on the ground. If the

Question

A peacock sitting on the top of a tree of height 10 m observes a snake moving on the ground. If the snake is $10 \sqrt{3} \mathrm{~m}$ away from the base of the tree, then angle of depression of the snake from the eye of the peacock is\

Professor PC Thomas Classes · Answer

(a): Let $P Q=10 \mathrm{~m}$ be a tree, $S$ be a snake at a distance of $10 \sqrt{3} \mathrm{~m}$ from the base of tree and $Q$ be the angle of depression from point $P$.\ $	herefore \quad \angle P S Q=	heta$\ In $	riangle P S Q$,\ $	an 	heta=\frac{P Q}{S Q}$\ $\Rightarrow 	an 	heta=\frac{10}{10 \sqrt{3}}=\frac{1}{\sqrt{3}}=	an 30^{\circ}$\ $\Rightarrow 	heta=30^{\circ}$ $$ 	ext { Concept Applied -  } 	an 30^{\circ}=\frac{1}{\sqrt{3}} $$