From a point on the ground, which is 30 m away from the foot of a vertical tower, the angle of eleva

Question

From a point on the ground, which is 30 m away from the foot of a vertical tower, the angle of elevation of the top of the tower is found to be $60^{\circ}$. The height (in metres) of the tower is :\

Professor PC Thomas Classes · Answer

(b):Let $A B$ be the tower and $C$ be the point which is 30 m away from the foot of the tower.\ $	herefore \quad$ Angle of elevation from C is $60^{\circ}$.\ $\Rightarrow \frac{A B}{B C}=	an 60^{\circ}$\ $\Rightarrow \frac{A B}{30}=\sqrt{3}$\ $	herefore A B=30 \sqrt{3} \mathrm{~m}$.\