A chord of a circle of radius 10 cm subtends a right angle at its centre. The length of the chord (i

Question

A chord of a circle of radius 10 cm subtends a right angle at its centre. The length of the chord (in cm ) is:\

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(b): Given, $O A=O B=10 \mathrm{~cm}$ (radii of circle) In right $	riangle O A B$,\ $(A B)^{2}=(O A)^{2}+(O B)^{2}$ [By Pythagoras theorem]\ $\Rightarrow(A B)^{2}=(10)^{2}+(10)^{2}$\ $\Rightarrow(A B)^{2}=100+100$\ $\Rightarrow A B=\sqrt{200}$\ $\Rightarrow A B=10 \sqrt{2} \mathrm{~cm}$\