The area swept by 7 cm long minute hand of a clock in 10 minutes is\

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Professor PC Thomas Classes · Answer

(d):Angle formed by minute hand of a clock in 60 minutes $=360^{\circ}$\ ∴ Angle formed by minute hand of a clock in 10 minutes\ $=\frac{10}{60} 	imes 360^{\circ}=60^{\circ}$\ Length of minute hand of a clock $=$ radius $=7 \mathrm{~cm}$\ $	herefore \quad$ Required area $$ =\pi r^{2} 	imes \frac{	heta}{360^{\circ}}=\frac{22}{7} 	imes 7 	imes 7 	imes \frac{60^{\circ}}{360^{\circ}}=\frac{77}{3} \mathrm{~cm}^{2}=25 \frac{2}{3} \mathrm{~cm}^{2} $$ Concept Applied - Area of sector $=\pi r^{2} 	imes \frac{	heta}{360^{\circ}}$