Consider the following reactions :
$\mathrm{NaCl}+\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7+\mathrm{H}

Question

Consider the following reactions :
$\mathrm{NaCl}+\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{~A}+\mathrm{KHSO}_4+\mathrm{NaHSO}_4+\mathrm{H}_2 \mathrm{O}$
$\mathrm{A}+\mathrm{NaOH} \rightarrow \mathrm{B}+\mathrm{NaCl}+\mathrm{H}_2 \mathrm{O}$
$\mathrm{B}+\mathrm{H}_2 \mathrm{SO}_4+\mathrm{H}_2 \mathrm{O}_2 \rightarrow \mathrm{C}+\mathrm{Na}_2 \mathrm{SO}_4+\mathrm{H}_2 \mathrm{O}$
In the product ' $\mathrm{C}^{\prime}$, ' $\mathrm{X}^{\prime}$ is the number of $\mathrm{O}_2^{2-}$ units, ' $\mathrm{Y}^{\prime}$ is the total number oxygen atoms present and ' $Z$ ' is the oxidation state of $C r$. The value of $X+Y+Z$ is $\_\_\_\_$.

Professor PC Thomas Classes · Answer

\