MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K .
$ \mathrm{MX

Question

MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K .
$ \mathrm{MX}(\mathrm{~s}) \rightleftharpoons \mathrm{M}^{+}(\mathrm{aq})+\mathrm{X}^{-}(\mathrm{aq}) ; \mathrm{K}_{\mathrm{sp}}=10^{-10} $
 If the standard reduction potential for $\mathrm{M}^{+}(\mathrm{aq}) \xrightarrow{+\mathrm{e}^{-}} \mathrm{M}(\mathrm{s})$ is $\left(\mathrm{E}_{\mathrm{M}^{+} / \mathrm{M}}^{\ominus}\right)=0.79 \mathrm{~V}$, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $\mathrm{E}_{\mathrm{X}^{-}}^{\ominus} / \mathrm{MX}(\mathrm{s}) / \mathrm{M}$ is $\_\_\_\_$ mV. (nearest integer) 
[Given : $\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{~V}$ ]

Professor PC Thomas Classes · Answer

See detailed solution for explanation.