The temperature at which the rate constants of the given below two gaseous reactions become equal is

Question

The temperature at which the rate constants of the given below two gaseous reactions become equal is $\_\_\_\_$ K. (Nearest integer)
 $ \begin{array}{ll} \mathrm{X} \longrightarrow \mathrm{Y} & \mathrm{k}_1=10^6 e^{\frac{-30000}{\mathrm{~T}}} \ \mathrm{P} \longrightarrow \mathrm{Q} & \mathrm{k}_2=10^4 e^{\frac{-24000}{\mathrm{~T}}} \end{array} $
Given: $\ln 10=2.303$

Professor PC Thomas Classes · Answer

See detailed solution for explanation.