An organic compound undergoes first order decomposition. The time taken for decomposition to $\left(

Question

An organic compound undergoes first order decomposition. The time taken for decomposition to $\left(\frac{1}{8}ight)^{	ext {th }}$ and $\left(\frac{1}{10}ight)^{	ext {th }}$ of its initial concentration are $\mathrm{t}_{1 / 8}$ and $\mathrm{t}_{1 / 10}$ respectively.

What is the value of $\frac{\mathrm{t}_{1 / 8}}{\mathrm{t}_{1 / 10}} 	imes 10$ ?
$
(\log 2=0.3)
$

Professor PC Thomas Classes · Answer

See detailed solution for explanation.