For the zener diode circuit shown, the current through the zener in mA is I . Find 2 I

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Professor PC Thomas Classes · Answer

Here, $R=5 	imes 10^3 \Omega, V_i=220 \mathrm{~V}$;
Zener voltage, $V_Z=50 \mathrm{~V}$
Load current, $I_L=\frac{V_Z}{R_L}=\frac{50}{20 	imes 10^3} =2.5 	imes 10^{-3} \mathrm{~A}$
Current through $R_r$
$$
\begin{aligned}
& I=\frac{220-50}{5 	imes 10^3}=34 	imes 10^{-3} \mathrm{~A} \
& 	herefore I_z=31.5 \mathrm{~mA} 	ext { and } 2 I_z=63 \mathrm{~mA}
\end{aligned}
$$