One litre of a sample of hard water contain $4.44 \mathrm{mg} \mathrm{~CaCl}_2$ and 1.9 mg of $\math

Question

One litre of a sample of hard water contain $4.44 \mathrm{mg} \mathrm{~CaCl}_2$ and 1.9 mg of $\mathrm{MgCl}_2$. What is the total hardness in terms of ppm of $\mathrm{CaCO}_3$ ?

Professor PC Thomas Classes · Answer

(d) $4.44 \mathrm{mg} \mathrm{CaCl}_2$ is equivalent to $4 \mathrm{mg} \mathrm{CaCO}_3$ $1.9 \mathrm{mg} \mathrm{MgCl}_2$ is equivalent to $2 \mathrm{mg} \mathrm{CaCO}_3$ Total mass of $\mathrm{CaCO}_3=6 \mathrm{mg}$ Hardness in ppm $=\frac{6 	imes 10^{-3}}{10^3} 	imes 10^6=6 \mathrm{ppm}$