How many minutes are required to deliver $3.21 imes 10^6$ coulombs using a current of 500 A used i

Question

How many minutes are required to deliver $3.21 	imes 10^6$ coulombs using a current of 500 A used in the commercial production of chlorine?

Professor PC Thomas Classes · Answer

$ \begin{aligned} & 	ext { (d) } 3.21 	imes 10^6=500 	imes t \ & 	herefore t=\frac{3.21 	imes 10^6}{500 	imes 60}=107 \mathrm{~min} . \end{aligned} $