An optically active compound ' $X$ ' has molecular formula $\mathrm{C}_4 \mathrm{H}_8 \mathrm{O}_3$.

Question

An optically active compound ' $X$ ' has molecular formula $\mathrm{C}_4 \mathrm{H}_8 \mathrm{O}_3$. It evolves $\mathrm{CO}_2$ with $\mathrm{NaHCO}_3$. ' $X$ ' reacts with $\mathrm{LiAlH}_4$ to give an achiral compound. ' $X$ ' is :

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