A scooter weighing 150 kg together with its rider is moving at $36 \mathrm{~km} / \mathrm{hr}$ and i

Question

A scooter weighing 150 kg together with its rider is moving at $36 \mathrm{~km} / \mathrm{hr}$ and is to take a circular turn of radius 30 m . If the horizontal force needed for the turn is to be supplied entirely by the normal force from the road, what should be the proper angle of banking? (Take $g= 10 \mathrm{~m} / \mathrm{s}^2$ )

Professor PC Thomas Classes · Answer

$	an 	heta=\frac{v^2}{r g}$
$\begin{gathered}\left(v=10 \mathrm{~m} / \mathrm{s}, r=30 \mathrm{~m}, g=10 \mathrm{~m} / \mathrm{s}^2ight) \ 	an 	heta=\frac{(10)^2}{30 	imes 10} \ 	an 	heta=\frac{100}{300} \ 	an 	heta=\frac{1}{3} \ 	heta=	an ^{-1}\left(\frac{1}{3}ight)\end{gathered}$