Henry Moseley in 1913 discovered the relationship between $X$-rays spectra and atomic number of the

Question

Henry Moseley in 1913 discovered the relationship between $X$-rays spectra and atomic number of the elements and given equation. $\sqrt{v}=a(Z-b)$ where, $a$ and $b$ are constants. If $O A=1$, then the incorrect statement about the element showing frequency of 225 Hz , is that\ \

Professor PC Thomas Classes · Answer

(b) : $\sqrt{v}=a Z-a b$ 
 Thus, represents a straight line, $y=m x-c$\ When $\sqrt{v}=0, a Z=a b$\ $Z=b=O A=1$\ When $Z=0, \sqrt{v}=-a b=-a \quad$ (since, $b=1$ )\ Slope $=a=	an 45^{\circ}=1$\ Thus, $a=1$ or $\sqrt{v}=Z-1 ; \sqrt{225}=Z-1 \Rightarrow Z=16$ 
Electronic configuration of atomic number 
$ 16=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4} $ 
Thus, it is $p$-block element thus, option (a) is correct.\ Group $=16$, valence electrons $=6$\ Period = 3, thus, option (d) is correct.\ It is non-metal, hence option (c) is correct, and option (b) is incorrect.\