Which molecule/ion out of the following does not contain unpaired electrons?\

Question

Professor PC Thomas Classes · Answer

(c) : $\mathrm{N}_{2}^{+}(13)=\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}, \pi 2 p_{x}^{2}=\pi 2 p_{y}^{2}, \sigma 2 p_{z}^{1} \mathrm{O}_{2}(16)=\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}, \sigma 2 p_{z}^{2}, \pi 2 p_{x}^{2}=\pi 2 p_{y}^{2}$, $\pi^{*} 2 p_{x}^{1}=\pi^{*} 2 p_{y}^{1}$\ $\mathrm{O}_{2}^{2-}(18)=\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}, \sigma 2 p_{z}^{2}, \pi 2 p_{x}^{2}=\pi 2 p_{y}^{2}$, $\pi^{*} 2 p_{x}^{2}=\pi^{*} 2 p_{y}^{2} \mathrm{B}_{2}(10)=\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}, \pi 2 p_{x}^{1}=\pi 2 p_{y}^{1}$\ Thus, $\mathrm{O}_{2}^{2-}$ does not contain unpaired electrons.\