Which of the following changes in the respective bond order values are caused by removal of an elect

Question

Which of the following changes in the respective bond order values are caused by removal of an electron from $\mathrm{N}_{2}$ and $\mathrm{F}_{2}$ molecules?\

Professor PC Thomas Classes · Answer

(d) : Electronic configuration of $\mathrm{N}_{2}$ molecule is\ $\sigma(1 s)^{2} \sigma^{*}(1 s)^{2} \sigma(2 s)^{2} \sigma^{*}(2 s)^{2} \pi\left(2 p_{x}ight)^{2}=\pi\left(2 p_{y}ight)^{2} \sigma\left(2 p_{z}ight)^{2}$\ B.O. $=\frac{1}{2}\left(N_{b}-N_{a}ight)=\frac{1}{2}(10-4)=3$ 
For the formation of $\mathrm{N}_{2}^{+}$, the bond order changes to 2.5.\ Electronic configuration of $F_{2}$ molecule is 
$ \begin{aligned} & \sigma(1 s)^{2} \sigma^{*}(1 s)^{2} \sigma(2 s)^{2} \sigma^{*}(2 s)^{2} \sigma\left(2 p_{z}ight)^{2} \pi\left(2 p_{x}ight)^{2}=\pi\left(2 p_{y}ight)^{2} \ & \pi^{*}\left(2 p_{x}ight)^{2}=\pi^{*}\left(2 p_{y}ight)^{2} \ & 	ext { B.O. }=\frac{1}{2}(10-8)=1 \end{aligned} $ 
For the formation of $\mathrm{F}_{2}^{+}$, the bond order changes to 1.5 .\