Which of the following is paramagnetic and has bond order 2?\

Question

Professor PC Thomas Classes · Answer

(a) : Electronic configuration of $\mathrm{O}_{2}$ is 
$ \begin{aligned} \sigma(1 s)^{2} \sigma^{*}(1 s)^{2} \sigma(2 s)^{2} \sigma^{*}(2 s)^{2} \sigma\left(2 p_{z}ight)^{2} \pi\left(2 p_{x}ight)^{2} & =\pi\left(2 p_{y}ight)^{2} \ \pi^{*}\left(2 p_{x}ight)^{1} & =\pi^{*}\left(2 p_{y}ight)^{1} \end{aligned} $
It has two unpaired electrons, so it is paramagnetic.\ Bond order $=\frac{1}{2}(10-6)=2$\