For a reaction, $P+Q \rightarrow R+S$. The value of $\Delta H$ is $-30 \mathrm{~kJ} \mathrm{~mol}^{-

Question

For a reaction, $P+Q ightarrow R+S$. The value of $\Delta H$ is $-30 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $\Delta S$ is $-100 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$. At what temperature the reaction will be at equilibrium?\

Professor PC Thomas Classes · Answer

(a) : $\Delta G=\Delta H-T \Delta S$,
At equilibrium, $\Delta G=0, \Delta H=T \Delta S$
$30000=T 	imes 100 ; T=300 \mathrm{~K}$ or $27^{\circ} \mathrm{C}$