A reaction attains equilibrium state under standard conditions, then what is incorrect for this?\

Question

Professor PC Thomas Classes · Answer

(a) : $\Delta G^{\circ}=0$ at equilibrium under standard state.
Thus, $\Delta H^{\circ}-T \Delta S^{\circ}=0$
Also, $\Delta G^{\circ}=2.303 R T \log K 	herefore K=1$ when $\Delta G^{\circ}=0$