The displacement-time graph of a particle of mass 5 kg moving along a straight line is shown in the

Question

The displacement-time graph of a particle of mass 5 kg moving along a straight line is shown in the figure. The impulse acting on the particle at $t=5 s$ is

Professor PC Thomas Classes · Answer

The velocity of the particle in $0<t<5 s$ is
$
v_i=\frac{4}{5} \mathrm{~ms}^{-1}
$
and at $t>5 s$ is $v_f=0$
$
	herefore \quad 	ext { Impulse }=m\left(v_f-v_iight)=5\left(0-\frac{4}{5}ight)=-4 \mathrm{~kg} \mathrm{~ms}^{-1}
$