A particle moves up an inclined plane with a constant acceleration $a^{\prime}$ with respect to it.

Question

A particle moves up an inclined plane with a constant acceleration $a^{\prime}$ with respect to it. The plane inclined at an angle $	heta$ with the horizontal also moves with constant acceleration a along the positive $x$-axis, as shown in figure. The acceleration of the particle with respect to ground is

Professor PC Thomas Classes · Answer

$ \mathbf{}$ $ a_x=a-a^{\prime} \cos 	heta 	ext { and } a_y=a^{\prime} \sin 	heta $