If the value of equilibrium constant $K_c$ for the reaction, $\mathrm{N}_2+3 \mathrm{H}_2 \rightleft

Question

If the value of equilibrium constant $K_c$ for the reaction, $\mathrm{N}_2+3 \mathrm{H}_2 \rightleftharpoons 2 \mathrm{NH}_3$ is 7 . The equilibrium constant for the reaction, $2 \mathrm{~N}_2+6 \mathrm{H}_2 \rightleftharpoons 4 \mathrm{NH}_3$ will be

Professor PC Thomas Classes · Answer

(a) : If reaction is multiplied by 2 , the equilibrium constant becomes square of the previous value. 
$ K=7^2=49 $