The expression for equilibrium constant, $K_c$ for the following reaction is
$ \mathrm{Fe}_{(a q)}^

Question

The expression for equilibrium constant, $K_c$ for the following reaction is 
$ \mathrm{Fe}_{(a q)}^{3+}+3 \mathrm{OH}_{(a q)}^{-} \rightleftharpoons \mathrm{Fe}(\mathrm{OH})_{3(s)} $

Professor PC Thomas Classes · Answer

(c) : $\mathrm{For}_{\mathrm{Fe}}^{(\mathrm{aq})}+3 \mathrm{OH}_{(\mathrm{aq})}^{-} \rightleftharpoons \mathrm{Fe}(\mathrm{OH})_{3(\mathrm{~s})}$ 
$ K_c=\frac{1}{\left[\mathrm{Fe}^{3+}\right]\left[\mathrm{OH}^{-}\right]^3} $