Consider the equilibrium set up :
$
2 \mathrm{H}_{2(g)}+\mathrm{CO}_{(g)} \rightleftharpoons \mathrm

Question

Consider the equilibrium set up :
$
2 \mathrm{H}_{2(g)}+\mathrm{CO}_{(g)} \rightleftharpoons \mathrm{CH}_3 \mathrm{OH}_{(g)}
$
What will be the effect of the following on the equilibrium of the reaction?
(i) Addition of $\mathrm{H}_2$
(ii) Addition of $\mathrm{CH}_3 \mathrm{OH}$
(iii) Removal of CO
(iv) Removal of $\mathrm{CH}_3 \mathrm{OH}$

Professor PC Thomas Classes · Answer

(a) : (i) Increase in concentration of reactants favours forward reaction. (ii) Increase in concentration of products favours backward reaction. 
(iii) Removal of CO will favour backward reaction (decrease in concentration of reactants). 
(iv) Removal of $\mathrm{CH}_3 \mathrm{OH}$ will favour forward reaction (increase in concentration of products).