In a potentiometer arrangement, a cell of emf 1.5 V gives a balance point at 27 cm length of wire. I

Question

In a potentiometer arrangement, a cell of emf 1.5 V gives a balance point at 27 cm length of wire. If the cell is replaced by another cell and balance point shifts to 54 cm , the emf of the second cell is

Professor PC Thomas Classes · Answer

$\frac{E_1}{E_2} = \frac{l_1}{l_2} \implies \frac{1.5}{E_2} = \frac{27}{54} \implies E_2 = 3.0 	ext{ V}$.