Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of

Question

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is $300 \mathrm{~m} / \mathrm{s}$. What is the phase difference between the oscillations of two points?

Professor PC Thomas Classes · Answer

$\lambda = v 	imes T = 300 	imes 0.05 = 15 	ext{ m}$. Path difference $\Delta x = 15 - 10 = 5 	ext{ m}$. Phase diff $\Delta \phi = \frac{2\pi}{\lambda}\Delta x = \frac{2\pi}{15}(5) = \frac{2\pi}{3}$.