A block of mass 5 kg is placed at rest and a table of rough surface. Now, if a force of 30 N is appl

Question

A block of mass 5 kg is placed at rest and a table of rough surface. Now, if a force of 30 N is applied in the direction parallel to surface of the table, the block slides through a distance of 50 m in an interval of time 10 s . Coefficient of kinetic friction is ( given, $g=10 \mathrm{~ms}^{-2}$ )

Professor PC Thomas Classes · Answer

$s = \frac{1}{2}at^2 \implies 50 = \frac{1}{2}a(100) \implies a = 1 	ext{ m/s}^2$.\ Equation: $F - \mu mg = ma \implies 30 - \mu(50) = 5(1) \implies \mu = 0.5$.