In the wave equation, $Y=0.5 \sin \frac{2 \pi}{\lambda}(400 t-x)$ the velocity of wave will be

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Professor PC Thomas Classes · Answer

Comparing with $y = A\sin(\omega t - kx)$, velocity $v = \frac{\omega}{k} = \frac{400(2\pi/\lambda)}{2\pi/\lambda} = 400 	ext{ m/s}$.