A string is wound around a hollow cylinder of mass 5 kg and radius 0.5 m . If the string is now pull

Question

A string is wound around a hollow cylinder of mass 5 kg and radius 0.5 m . If the string is now pulled with a horizontal force of 40 N , and the cylinder is rolling without slipping on a horizontal surface ( see the figure ) then the angular acceleration of the cylinder will be (neglect the mass and thickness of the string)

Professor PC Thomas Classes · Answer

Torque about contact point: $	au = F(2R) = 40(1) = 40$. $I_{contact} = mR^2 + mR^2 = 2.5$. $\alpha = \frac{	au}{I} = \frac{40}{2.5} = 16 	ext{ rad/s}^2$.