Number of divisors of the form $4 n+2(n \geq 0)$ of the integer 280 is

Question

Professor PC Thomas Classes · Answer

Divisors of form $4n+2$ are strictly singly-even. $280 = 2^3 	imes 5 	imes 7$. Odd divisors of $280$ are $(1+1)(1+1) = 4$. Multiply each by 2.