A cricketer can throw a ball to a maximum horizontal distance of $100 ext{ m}$. How much high above

Question

A cricketer can throw a ball to a maximum horizontal distance of $100	ext{ m}$. How much high above the ground can the cricketer throw the same ball vertically upward?

Professor PC Thomas Classes · Answer

Maximum horizontal range $R_{max} = \frac{u^2}{g}$ (occurs at $	heta = 45^\circ$). So, $\frac{u^2}{g} = 100	ext{ m}$. When thrown vertically upward ($	heta = 90^\circ$), max height $h_{max} = \frac{u^2}{2g}$. Therefore, $h_{max} = \frac{100}{2} = 50	ext{ m}$.