Two projectiles are thrown with the same initial velocity $u$ at angles $ heta$ and $(90^\circ -

Question

Two projectiles are thrown with the same initial velocity $u$ at angles $	heta$ and $(90^\circ - 	heta)$ to the horizontal. What is the ratio of their maximum heights?

Professor PC Thomas Classes · Answer

$h_1 = \frac{u^2\sin^2	heta}{2g}$ and $h_2 = \frac{u^2\sin^2(90^\circ - 	heta)}{2g} = \frac{u^2\cos^2	heta}{2g}$. The ratio $\frac{h_1}{h_2} = \frac{\sin^2	heta}{\cos^2	heta} = 	an^2	heta$.