In an experiment, an initial volume of $100.0 ext{ L}$ of water is subjected to a pressure increase

Question

In an experiment, an initial volume of $100.0	ext{ L}$ of water is subjected to a pressure increase of $100.0	ext{ atm}$ ($1	ext{ atm} = 1.013 	imes 10^5	ext{ Pa}$). If the volume decreases by $0.5	ext{ L}$, what is the computed bulk modulus of water?

Professor PC Thomas Classes · Answer

Pressure increase $\Delta P = 100 	imes 1.013 	imes 10^5 = 1.013 	imes 10^7	ext{ Pa}$. Volume strain $\frac{\Delta V}{V} = \frac{0.5}{100.0} = 0.005$. Bulk modulus $B = \frac{\Delta P}{\Delta V / V} = \frac{1.013 	imes 10^7}{0.005} = 2.026 	imes 10^9	ext{ Pa}$.