A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspende

Question

A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30 degrees with the direction of a uniform horizontal magnetic field of 0.80 T. What is the magnitude of torque experienced by the coil?

Professor PC Thomas Classes · Answer

Area $A = (0.10)^2 = 0.01	ext{ m}^2$. Torque $	au = NIAB \sin	heta = 20 	imes 12 	imes 0.01 	imes 0.80 	imes \sin(30^\circ) = 0.96	ext{ N m}$.