What is the 'spin-only' magnetic moment of the $ ext{Ce}^{3+}$ ion? (Atomic number of Ce = 58)

Question

What is the 'spin-only' magnetic moment of the $	ext{Ce}^{3+}$ ion? (Atomic number of Ce = 58)

Professor PC Thomas Classes · Answer

Cerium (Z=58) is $[	ext{Xe}] 4f^1 5d^1 6s^2$. The $	ext{Ce}^{3+}$ ion has lost 3 electrons (two from 6s, one from 5d), leaving the configuration $[	ext{Xe}] 4f^1$. It has 1 unpaired electron. Magnetic moment $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73	ext{ BM}$.