In the complex $ ext{Na}_2[ ext{CrF}_4 ext{O}]$, what is the oxidation state of Chromium?

Question

In the complex $	ext{Na}_2[	ext{CrF}_4	ext{O}]$, what is the oxidation state of Chromium?

Professor PC Thomas Classes · Answer

Let the oxidation state of Cr be $x$. The overall charge on the complex anion $[	ext{CrF}_4	ext{O}]^{2-}$ is -2. Thus, $x + 4(-1) + (-2) = -2$, which simplifies to $x - 6 = -2$, giving $x = +4$.