The acceleration due to gravity on the moon's surface is $1.7 \mathrm{~m} / \mathrm{sec}^2$ and acce

Question

The acceleration due to gravity on the moon's surface is $1.7 \mathrm{~m} / \mathrm{sec}^2$ and acceleration due to gravity on earth is $9.8 \mathrm{~m} / \mathrm{sec}^2$. If time period of a simple pendulum on the earth is 3.5 sec , its time period on the moon is

Professor PC Thomas Classes · Answer

$T \propto \frac{1}{\sqrt{g}}$. $\frac{T_m}{T_e} = \sqrt{\frac{g_e}{g_m}} = \sqrt{\frac{9.8}{1.7}} \approx 2.4$. $T_m = 3.5 	imes 2.4 = 8.4$ sec.